AccelePrep for the ACT Test 2nd Edition Student Text

C HAPTER 5 | H YPER P REP M ATH • 117

If you still aren’t sure of your answer, measure the chord (16) and take away the segment from the chord to O (6) so that you are left with 10. Now measure r : 10. 5. You can solve this problem by using the special properties of 45°-45°- 90° and 30°-60°-90° triangles. Or you can just measure. There’s no Ž‹‡ –‘ ‡ƒ•—”‡ǡ „—– ›‘—ǯ”‡ •—’’‘•‡† –‘ ϐ‹† –Š‡ †‹•–ƒ…‡ ˆ”‘ –Š‡ ’‡ƒ ‘ˆ –Š‡ ”‘‘ˆ –‘ –Š‡ ϐŽ‘‘”ǡ •‘ Œ—•– —•‡ ›‘—” ƒ•™‡” •Š‡‡– ƒ• ƒ •–”ƒ‹‰Š– ‡†‰‡Ǥ ƒ” –Š‡ †‹•–ƒ…‡ ˆ”‘ –Š‡ ’‡ƒ –‘ –Š‡ ϐŽ‘‘”Ǥ Š‡…‘˜‡”– –Šƒ– distance to a number by comparing the marked distance with known quantities on the drawing. You can see that the distance from the roof –‘ –Š‡ ϐŽ‘‘” ‹• ˜‡”› •‹‹Žƒ” –‘ –Š‡ Ž‡‰–Š ‘ˆ –Š‡ „ƒ”ǡ ͳͺ ˆ‡‡–ǡ •‘ ȋ Ȍ must be correct. 6. Mark off the length of AE on a piece of paper—this length is . 1.4 . 2 Compare this length of AE to one side of the square—the side is about 1.5 times as long as AE , or 2 units. Thus, the area of the square is approximately 2 4 2 , so (H) appears correct. Double-check the ƒ•™‡”…Š‘‹…‡• ‘ „‘–Š •‹†‡• ‘ˆ ȋ ȌǤ ȋ Ȍ ‹• ƒ’’”‘š‹ƒ–‡Ž› ʹǤͺǢ ȋ Ȍ ‹• approximately 5.6. Therefore, (H) is correct. 7. Š‡ Dz‘ˆϐ‹…‹ƒŽdz ƒ–Š ƒ’’”‘ƒ…Š –‘ –Š‹• ’”‘„Ž‡ ‹• –‘ —•‡ –Š‡ ‹ˆ‘”ƒ–‹‘ given in the graph to derive the equation for the line: m Slope 4 0 0 2 4 2 2 1 run rise ^ h The equation of a line can be written as y mx b , so plug in the given values: –2 = b Therefore, y x 2 2 , (B). If you can remember this procedure, great! But if you’re a little fuzzy ‘ –Š‡ †‡–ƒ‹Ž•ǡ Œ—•– ”‡‡„‡” –Šƒ– ‘‡ ‘ˆ –Š‘•‡ ϐ‹˜‡ ƒ•™‡”…Š‘‹…‡• IS the equation for the line. Pick a pair of ( x , y ) points from the graph and substitute those values into the answer choices. For example, we can see from the diagram that (4,0) is a point on the line. We can substitute x = 4 and y = 0 into each answer choice: A. & 0 2 4 4 0 6 (Wrong) B. & 0 2 4

2 0 0 (Correct) C. & 0 4 1 0 5 (Wrong) D. & 0 2 4 2 0 10 ^ h (Wrong) E. & 0 2 4 2 0 6 ^ h (Wrong)