Victory fot the ACT Exam 16e ST Sample

190 • M ATH

SOLIDS

26. To fhlee np gr itshms 1b2e,l o1 w6 , ha na sd b2a0s ec se nwt ii mt hestiedress. Tc ehnet idmi set taenrcse. Wb eht awt ei es nt ht eh el abt ea rs ae ls si us r3f a0c e area, in square centimeters, of the prism?

28. Tushiengvotlhuemfoeromf ualcaone can be found 3 1 V r h 2 = r . If a cone has a height of 10 cm and a volume of 120 cm r 3 , what is the diameter of its base, in centimeters? F. G. H. 3 1 6 6 2 J. 72 29. AT hceo ns isl tor ui sc at i oc ynl icnodme pr awniyt hi sa bhuei ml d ii snpghae sr ei l o . of ene tt oapn. dT thhee dhi ea img he tt eorf ot hf et hcey lciynldi nedr ei sr 4i s04 2 fseileot,. iHnocwubmicufceheth?ay can be stored in the

Don’t Forget This! Cube volume: 3 Cube surface area: SA x 6 = 2 Prism volume: V = bwh Prism surface area: SA = 2 bw + 2 wh + 2 bh Cylinder volume: 0 V r h 2 = r Caryelian:der lateral surface 2 LSA rh = r 0 Caryelian:der total surface TSA =2 π rh +2 π r 2 Sphere volume: V r = r 3 4 3 Sphere surface area: 4 SA r 2 = r Cube V = x 3 SA = 6 x 2 Prism V x = 0

F G . . 1 1 , , 4 6 4 3 0 2 H. J. 6 4 0 8 0 0 27. Wi n hs aqtuiasr tehien cahpepsr,ooxfi ma ba tael l swu ri tfha cae laarregae,s t circumference of 12 r inches? ( 4 SA r 2 = r Sphere )

A. 12 r B. 36 r C. 144 r D. 576 r

A. 23,814 r B. 29,988 r C. 711,774 r D. 717,948 r

V = bwh SA = 2 bw + 2 wh + 2 bh Cylinder

0 V r h 2 r = 2 0 LSA rh r = 2 2 0 TSA rh r 2 r r Sphere

3 4 V r 3 r = 4 SA r 2 r =